Find the Roots (Zeros) x^4+2x^3+7x^2-8x+12

$x^{4} + 2 x^{3} + 7 x^{2} - 8 x + 12$

Step 1

Set $x^{4} + 2 x^{3} + 7 x^{2} - 8 x + 12$ equal to $0$ .

$x^{4} + 2 x^{3} + 7 x^{2} - 8 x + 12 = 0$

Step 2

Graph each side of the equation. The solution is the x-value of the point of intersection.

No solution