Find the Roots (Zeros) (x+5)(x-5)=-9

$(x + 5) (x - 5) = - 9$

Simplify $(x + 5) (x - 5)$ .

Expand $(x + 5) (x - 5)$ using the FOIL Method.

Apply the distributive property.

$x (x - 5) + 5 (x - 5) = - 9$

Apply the distributive property.

$x \cdot x + x \cdot - 5 + 5 (x - 5) = - 9$

Apply the distributive property.

$x \cdot x + x \cdot - 5 + 5 x + 5 \cdot - 5 = - 9$

Simplify terms.

Combine the opposite terms in $x \cdot x + x \cdot - 5 + 5 x + 5 \cdot - 5$ .

Reorder the factors in the terms $x \cdot - 5$ and $5 x$ .

$x \cdot x - 5 x + 5 x + 5 \cdot - 5 = - 9$

Add $- 5 x$ and $5 x$ .

$x \cdot x + 0 + 5 \cdot - 5 = - 9$

Add $x \cdot x$ and $0$ .

$x \cdot x + 5 \cdot - 5 = - 9$

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + 5 \cdot - 5 = - 9$

Multiply $5$ by $- 5$ .

$x^{2} - 25 = - 9$

Move all terms not containing $x$ to the right side of the equation.

Add $25$ to both sides of the equation.

$x^{2} = - 9 + 25$

Add $- 9$ and $25$ .

$x^{2} = 16$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{16}$

Simplify $\pm \sqrt{16}$ .

Rewrite $16$ as $4^{2}$ .

$x = \pm \sqrt{4^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 4$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 4$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 4$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 4, - 4$