Find the Roots (Zeros) x^7+128=0

$x^{7} + 128 = 0$

Step 1

Subtract $128$ from both sides of the equation.

$x^{7} = - 128$

Step 2

Take the 7th root of both sides of the equation to eliminate the exponent on the left side.

$x = \sqrt[7]{- 128}$

Step 3

Simplify $\sqrt[7]{- 128}$ .

Rewrite $- 128$ as ${(- 2)}^{7}$ .

$x = \sqrt[7]{{(- 2)}^{7}}$

Pull terms out from under the radical, assuming real numbers.

$x = - 2$

Step 4