Find the Roots (Zeros) y=16-4x^2

$y = 16 - 4 x^{2}$

Step 1

Set $16 - 4 x^{2}$ equal to $0$ .

$16 - 4 x^{2} = 0$

Step 2

Solve for $x$ .

Subtract $16$ from both sides of the equation.

$- 4 x^{2} = - 16$

Divide each term in $- 4 x^{2} = - 16$ by $- 4$ and simplify.

Divide each term in $- 4 x^{2} = - 16$ by $- 4$ .

$\frac{- 4 x^{2}}{- 4} = \frac{- 16}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 x^{2}}{- 4} = \frac{- 16}{- 4}$

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{- 16}{- 4}$

Simplify the right side.

Divide $- 16$ by $- 4$ .

$x^{2} = 4$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{4}$

Simplify $\pm \sqrt{4}$ .

Rewrite $4$ as $2^{2}$ .

$x = \pm \sqrt{2^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 2$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 2$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 2$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 2, - 2$

Step 3