Find the Roots (Zeros) y=(2x+8)/(18x^2+96x-72)

$y = \frac{2 x + 8}{18 x^{2} + 96 x - 72}$

Set $\frac{2 x + 8}{18 x^{2} + 96 x - 72}$ equal to $0$ .

$\frac{2 x + 8}{18 x^{2} + 96 x - 72} = 0$

Solve for $x$ .

Set the numerator equal to zero.

$2 x + 8 = 0$

Solve the equation for $x$ .

Subtract $8$ from both sides of the equation.

$2 x = - 8$

Divide each term in $2 x = - 8$ by $2$ and simplify.

Divide each term in $2 x = - 8$ by $2$ .

$\frac{2 x}{2} = \frac{- 8}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 8}{2}$

Divide $x$ by $1$ .

$x = \frac{- 8}{2}$

Simplify the right side.

Divide $- 8$ by $2$ .

$x = - 4$