Find the Roots (Zeros) y=-(x-1)(x+3)

$y = - (x - 1) (x + 3)$

Set $- (x - 1) (x + 3)$ equal to $0$ .

$- (x - 1) (x + 3) = 0$

Solve for $x$ .

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 1 = 0$

$x + 3 = 0$

Set $x - 1$ equal to $0$ and solve for $x$ .

Set $x - 1$ equal to $0$ .

$x - 1 = 0$

Add $1$ to both sides of the equation.

$x = 1$

Set $x + 3$ equal to $0$ and solve for $x$ .

Set $x + 3$ equal to $0$ .

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

The final solution is all the values that make $- (x - 1) (x + 3) = 0$ true.

$x = 1, - 3$