Find the Roots (Zeros) y=x^2+14x+24

$y = x^{2} + 14 x + 24$

Step 1

Set $x^{2} + 14 x + 24$ equal to $0$ .

$x^{2} + 14 x + 24 = 0$

Step 2

Solve for $x$ .

Factor $x^{2} + 14 x + 24$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $24$ and whose sum is $14$ .

$2, 12$

Write the factored form using these integers.

$(x + 2) (x + 12) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 2 = 0$

$x + 12 = 0$

Set $x + 2$ equal to $0$ and solve for $x$ .

Set $x + 2$ equal to $0$ .

$x + 2 = 0$

Subtract $2$ from both sides of the equation.

$x = - 2$

Set $x + 12$ equal to $0$ and solve for $x$ .

Set $x + 12$ equal to $0$ .

$x + 12 = 0$

Subtract $12$ from both sides of the equation.

$x = - 12$

The final solution is all the values that make $(x + 2) (x + 12) = 0$ true.

$x = - 2, - 12$

Step 3

Find the Roots (Zeros) y=x^2+14x+24

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