Find the Roots (Zeros) y=(x+3)(x-4)(x-5)

$y = (x + 3) (x - 4) (x - 5)$

Step 1

Set $(x + 3) (x - 4) (x - 5)$ equal to $0$ .

$(x + 3) (x - 4) (x - 5) = 0$

Step 2

Solve for $x$ .

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 3 = 0$

$x - 4 = 0$

$x - 5 = 0$

Set $x + 3$ equal to $0$ and solve for $x$ .

Set $x + 3$ equal to $0$ .

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

Set $x - 4$ equal to $0$ and solve for $x$ .

Set $x - 4$ equal to $0$ .

$x - 4 = 0$

Add $4$ to both sides of the equation.

$x = 4$

Set $x - 5$ equal to $0$ and solve for $x$ .

Set $x - 5$ equal to $0$ .

$x - 5 = 0$

Add $5$ to both sides of the equation.

$x = 5$

The final solution is all the values that make $(x + 3) (x - 4) (x - 5) = 0$ true.

$x = - 3, 4, 5$

Step 3