Find the Sample Standard Deviation 16 , 21 , 17 , 22 , 15 , 10 , 21

The mean of a set of numbers is the sum divided by the number of terms.

Simplify the numerator.

Divide.

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

Convert ${\displaystyle 16}$ to a decimal value.

Convert ${\displaystyle 21}$ to a decimal value.

Convert ${\displaystyle 17}$ to a decimal value.

Convert ${\displaystyle 22}$ to a decimal value.

Convert ${\displaystyle 15}$ to a decimal value.

Convert ${\displaystyle 10}$ to a decimal value.

Convert ${\displaystyle 21}$ to a decimal value.

The simplified values are ${\displaystyle 16,21,17,22,15,10,21}$.

Subtract ${\displaystyle 17.4}$ from ${\displaystyle 16}$.

Raise ${\displaystyle -1.4}$ to the power of ${\displaystyle 2}$.

Subtract ${\displaystyle 17.4}$ from ${\displaystyle 21}$.

Raise ${\displaystyle 3.6}$ to the power of ${\displaystyle 2}$.

Subtract ${\displaystyle 17.4}$ from ${\displaystyle 17}$.

Raise ${\displaystyle -0.4}$ to the power of ${\displaystyle 2}$.

Subtract ${\displaystyle 17.4}$ from ${\displaystyle 22}$.

Raise ${\displaystyle 4.6}$ to the power of ${\displaystyle 2}$.

Subtract ${\displaystyle 17.4}$ from ${\displaystyle 15}$.

Raise ${\displaystyle -2.4}$ to the power of ${\displaystyle 2}$.

Subtract ${\displaystyle 17.4}$ from ${\displaystyle 10}$.

Raise ${\displaystyle -7.4}$ to the power of ${\displaystyle 2}$.

Subtract ${\displaystyle 17.4}$ from ${\displaystyle 21}$.

Raise ${\displaystyle 3.6}$ to the power of ${\displaystyle 2}$.

Add ${\displaystyle 1.96}$ and ${\displaystyle 12.96}$.

Add ${\displaystyle 14.92}$ and ${\displaystyle 0.16}$.

Add ${\displaystyle 15.08}$ and ${\displaystyle 21.16}$.

Add ${\displaystyle 36.24}$ and ${\displaystyle 5.76}$.

Add ${\displaystyle 42}$ and ${\displaystyle 54.76}$.

Add ${\displaystyle 96.76}$ and ${\displaystyle 12.96}$.

Subtract ${\displaystyle 1}$ from ${\displaystyle 7}$.

Divide ${\displaystyle 109.72}$ by ${\displaystyle 6}$.