Find the Second Term a_n=2/5(5)^(n-1)

$a_{n} = \frac{2}{5} {(5)}^{n - 1}$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{2} = \frac{2}{5} \cdot {(5)}^{(2) - 1}$

Step 2

Subtract $1$ from $2$ .

$a_{2} = \frac{2}{5} \cdot 5$

Step 3

Cancel the common factor of $5$ .

Factor $5$ out of $5^{1}$ .

$a_{2} = \frac{2}{5} \cdot (5 \cdot 1)$

Cancel the common factor.

$a_{2} = \frac{2}{5} \cdot (5 \cdot 1)$

Rewrite the expression.

$a_{2} = 2$