Find the Second Term a_n=3(4)^(n-1)

$a_{n} = 3 {(4)}^{n - 1}$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{2} = 3 {(4)}^{(2) - 1}$

Step 2

Subtract $1$ from $2$ .

$a_{2} = 3 \cdot 4$

Step 3

Multiply $3$ by $4$ .

$a_{2} = 12$