Find the Second Term a_n=4(4)^n

$a_{n} = 4 {(4)}^{n}$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{2} = 4 {(4)}^{2}$

Step 2

Multiply $4$ by ${(4)}^{2}$ by adding the exponents.

Multiply $4$ by ${(4)}^{2}$ .

Raise $4$ to the power of $1$ .

$a_{2} = 4 {(4)}^{2}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$a_{2} = 4^{1 + 2}$

Add $1$ and $2$ .

$a_{2} = 4^{3}$

Step 3

Raise $4$ to the power of $3$ .

$a_{2} = 64$