Find the Second Term a_n=6(n-1)!

$a_{n} = 6 (n - 1)!$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{2} = 6 ((2) - 1)!$

Step 2

Subtract $1$ from $2$ .

$a_{2} = 6 (1)!$

Step 3

Expand $(1)!$ to $1$ .

$a_{2} = 6 \cdot 1$

Step 4

Multiply $6$ by $1$ .

$a_{2} = 6$