Find the Second Term a_n=((n+1)!)/(n+1)

$a_{n} = \frac{(n + 1)!}{n + 1}$

Substitute in the value of $n$ to find the $n$ th term.

$a_{2} = \frac{((2) + 1)!}{(2) + 1}$

Simplify the numerator.

Add $2$ and $1$ .

$a_{2} = \frac{(3)!}{2 + 1}$

Expand $(3)!$ to $3 \cdot 2 \cdot 1$ .

$a_{2} = \frac{3 \cdot 2 \cdot 1}{2 + 1}$

Simplify.

Multiply $3$ by $2$ .

$a_{2} = \frac{6 \cdot 1}{2 + 1}$

Multiply $6$ by $1$ .

$a_{2} = \frac{6}{2 + 1}$

Simplify the expression.

Add $2$ and $1$ .

$a_{2} = \frac{6}{3}$

Divide $6$ by $3$ .

$a_{2} = 2$