Find the Second Term a_n=((n+2)!)/(n+2)

$a_{n} = \frac{(n + 2)!}{n + 2}$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{2} = \frac{((2) + 2)!}{(2) + 2}$

Step 2

Simplify the numerator.

Add $2$ and $2$ .

$a_{2} = \frac{(4)!}{2 + 2}$

Expand $(4)!$ to $4 \cdot 3 \cdot 2 \cdot 1$ .

$a_{2} = \frac{4 \cdot 3 \cdot 2 \cdot 1}{2 + 2}$

Multiply $4 \cdot 3 \cdot 2 \cdot 1$ .

Multiply $4$ by $3$ .

$a_{2} = \frac{12 \cdot 2 \cdot 1}{2 + 2}$

Multiply $12$ by $2$ .

$a_{2} = \frac{24 \cdot 1}{2 + 2}$

Multiply $24$ by $1$ .

$a_{2} = \frac{24}{2 + 2}$

Step 3

Simplify the expression.

Add $2$ and $2$ .

$a_{2} = \frac{24}{4}$

Divide $24$ by $4$ .

$a_{2} = 6$