Find the Slope 17+3y=7x

$17 + 3 y = 7 x$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $17$ from both sides of the equation.

$3 y = 7 x - 17$

Divide each term in $3 y = 7 x - 17$ by $3$ and simplify.

Divide each term in $3 y = 7 x - 17$ by $3$ .

$\frac{3 y}{3} = \frac{7 x}{3} + \frac{- 17}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{7 x}{3} + \frac{- 17}{3}$

Divide $y$ by $1$ .

$y = \frac{7 x}{3} + \frac{- 17}{3}$

Simplify the right side.

Move the negative in front of the fraction.

$y = \frac{7 x}{3} - \frac{17}{3}$

Reorder terms.

$y = \frac{7}{3} x - \frac{17}{3}$

Step 2

Using the slope-intercept form, the slope is $\frac{7}{3}$ .

$m = \frac{7}{3}$

Step 3