Find the Slope -3x-3y=9

$- 3 x - 3 y = 9$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Add $3 x$ to both sides of the equation.

$- 3 y = 9 + 3 x$

Divide each term in $- 3 y = 9 + 3 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = 9 + 3 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{9}{- 3} + \frac{3 x}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{9}{- 3} + \frac{3 x}{- 3}$

Divide $y$ by $1$ .

$y = \frac{9}{- 3} + \frac{3 x}{- 3}$

Simplify the right side.

Simplify each term.

Divide $9$ by $- 3$ .

$y = - 3 + \frac{3 x}{- 3}$

Cancel the common factor of $3$ and $- 3$ .

Factor $3$ out of $3 x$ .

$y = - 3 + \frac{3 (x)}{- 3}$

Move the negative one from the denominator of $\frac{x}{- 1}$ .

$y = - 3 - 1 \cdot x$

Rewrite $- 1 \cdot x$ as $- x$ .

$y = - 3 - x$

Reorder $- 3$ and $- x$ .

$y = - x - 3$

Step 2

Using the slope-intercept form, the slope is $- 1$ .

$m = - 1$

Step 3