Find the Slope 3x-y=2

$3 x - y = 2$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $3 x$ from both sides of the equation.

$- y = 2 - 3 x$

Divide each term in $- y = 2 - 3 x$ by $- 1$ and simplify.

Divide each term in $- y = 2 - 3 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{2}{- 1} + \frac{- 3 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{2}{- 1} + \frac{- 3 x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{2}{- 1} + \frac{- 3 x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $2$ by $- 1$ .

$y = - 2 + \frac{- 3 x}{- 1}$

Move the negative one from the denominator of $\frac{- 3 x}{- 1}$ .

$y = - 2 - 1 \cdot (- 3 x)$

Rewrite $- 1 \cdot (- 3 x)$ as $- (- 3 x)$ .

$y = - 2 - (- 3 x)$

Multiply $- 3$ by $- 1$ .

$y = - 2 + 3 x$

Reorder $- 2$ and $3 x$ .

$y = 3 x - 2$

Step 2

Using the slope-intercept form, the slope is $3$ .

$m = 3$

Step 3