Find the Slope 4x-y=8

$4 x - y = 8$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $4 x$ from both sides of the equation.

$- y = 8 - 4 x$

Divide each term in $- y = 8 - 4 x$ by $- 1$ and simplify.

Divide each term in $- y = 8 - 4 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{8}{- 1} + \frac{- 4 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{8}{- 1} + \frac{- 4 x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{8}{- 1} + \frac{- 4 x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $8$ by $- 1$ .

$y = - 8 + \frac{- 4 x}{- 1}$

Move the negative one from the denominator of $\frac{- 4 x}{- 1}$ .

$y = - 8 - 1 \cdot (- 4 x)$

Rewrite $- 1 \cdot (- 4 x)$ as $- (- 4 x)$ .

$y = - 8 - (- 4 x)$

Multiply $- 4$ by $- 1$ .

$y = - 8 + 4 x$

Reorder $- 8$ and $4 x$ .

$y = 4 x - 8$

Step 2

Using the slope-intercept form, the slope is $4$ .

$m = 4$

Step 3