Find the Slope and y-intercept (-1,4) , (3,8)

$(- 1, 4)$ , $(3, 8)$

Find the value of the slope.

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{8 - (4)}{3 - (- 1)}$

Simplify.

Simplify the numerator.

Multiply $- 1$ by $4$ .

$m = \frac{8 - 4}{3 - (- 1)}$

Subtract $4$ from $8$ .

$m = \frac{4}{3 - (- 1)}$

Simplify the denominator.

Multiply $- 1$ by $- 1$ .

$m = \frac{4}{3 + 1}$

Add $3$ and $1$ .

$m = \frac{4}{4}$

Divide $4$ by $4$ .

$m = 1$

Find the value of the y-intercept.

Substitute the value of $m$ into the slope-intercept form of the equation, $y = m x + b$ .

$y = (1) \cdot x + b$

Substitute the value of $x$ into the slope-intercept form of the equation, $y = m x + b$ .

$y = (1) \cdot (- 1) + b$

Substitute the value of $y$ into the slope-intercept form of the equation, $y = m x + b$ .

$4 = (1) \cdot (- 1) + b$

Rewrite the equation as $(1) \cdot (- 1) + b = 4$ .

$(1) \cdot (- 1) + b = 4$

Multiply $- 1$ by $1$ .

$- 1 + b = 4$

Move all terms not containing $b$ to the right side of the equation.

Add $1$ to both sides of the equation.

$b = 4 + 1$

Add $4$ and $1$ .

$b = 5$

List the slope and y-intercept.

Slope: $1$

y-intercept: $(0, 5)$

Find the Slope and y-intercept (-1,4) , (3,8)

Related Questions

Support LCMGCF.com by disabling your adblocker.