Find the Slope and y-intercept -12x-3y=-3

$- 12 x - 3 y = - 3$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Add $12 x$ to both sides of the equation.

$- 3 y = - 3 + 12 x$

Divide each term in $- 3 y = - 3 + 12 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = - 3 + 12 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{- 3}{- 3} + \frac{12 x}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{- 3}{- 3} + \frac{12 x}{- 3}$

Divide $y$ by $1$ .

$y = \frac{- 3}{- 3} + \frac{12 x}{- 3}$

Simplify the right side.

Simplify each term.

Divide $- 3$ by $- 3$ .

$y = 1 + \frac{12 x}{- 3}$

Cancel the common factor of $12$ and $- 3$ .

Factor $3$ out of $12 x$ .

$y = 1 + \frac{3 (4 x)}{- 3}$

Move the negative one from the denominator of $\frac{4 x}{- 1}$ .

$y = 1 - 1 \cdot (4 x)$

Rewrite $- 1 \cdot (4 x)$ as $- (4 x)$ .

$y = 1 - (4 x)$

Multiply $4$ by $- 1$ .

$y = 1 - 4 x$

Reorder $1$ and $- 4 x$ .

$y = - 4 x + 1$

Step 2

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 4$

$b = 1$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 4$

y-intercept: $(0, 1)$

Slope: $- 4$

y-intercept: $(0, 1)$

Step 3