Find the Slope and y-intercept 12x-3y=3

$12 x - 3 y = 3$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $12 x$ from both sides of the equation.

$- 3 y = 3 - 12 x$

Divide each term in $- 3 y = 3 - 12 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = 3 - 12 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{3}{- 3} + \frac{- 12 x}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{3}{- 3} + \frac{- 12 x}{- 3}$

Divide $y$ by $1$ .

$y = \frac{3}{- 3} + \frac{- 12 x}{- 3}$

Simplify the right side.

Simplify each term.

Divide $3$ by $- 3$ .

$y = - 1 + \frac{- 12 x}{- 3}$

Cancel the common factor of $- 12$ and $- 3$ .

Factor $- 3$ out of $- 12 x$ .

$y = - 1 + \frac{- 3 (4 x)}{- 3}$

Cancel the common factors.

Factor $- 3$ out of $- 3$ .

$y = - 1 + \frac{- 3 (4 x)}{- 3 (1)}$

Cancel the common factor.

$y = - 1 + \frac{- 3 (4 x)}{- 3 \cdot 1}$

Rewrite the expression.

$y = - 1 + \frac{4 x}{1}$

Divide $4 x$ by $1$ .

$y = - 1 + 4 x$

Reorder $- 1$ and $4 x$ .

$y = 4 x - 1$

Step 2

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 4$

$b = - 1$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $4$

y-intercept: $(0, - 1)$

Slope: $4$

y-intercept: $(0, - 1)$

Step 3