Find the Slope and y-intercept 2(y+1)=10x+3

$2 (y + 1) = 10 x + 3$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify the left side.

Simplify $2 (y + 1)$ .

Apply the distributive property.

$2 y + 2 \cdot 1 = 10 x + 3$

Multiply $2$ by $1$ .

$2 y + 2 = 10 x + 3$

Move all terms not containing $y$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$2 y = 10 x + 3 - 2$

Subtract $2$ from $3$ .

$2 y = 10 x + 1$

Divide each term in $2 y = 10 x + 1$ by $2$ and simplify.

Divide each term in $2 y = 10 x + 1$ by $2$ .

$\frac{2 y}{2} = \frac{10 x}{2} + \frac{1}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{10 x}{2} + \frac{1}{2}$

Divide $y$ by $1$ .

$y = \frac{10 x}{2} + \frac{1}{2}$

Simplify the right side.

Cancel the common factor of $10$ and $2$ .

Factor $2$ out of $10 x$ .

$y = \frac{2 (5 x)}{2} + \frac{1}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$y = \frac{2 (5 x)}{2 (1)} + \frac{1}{2}$

Cancel the common factor.

$y = \frac{2 (5 x)}{2 \cdot 1} + \frac{1}{2}$

Rewrite the expression.

$y = \frac{5 x}{1} + \frac{1}{2}$

Divide $5 x$ by $1$ .

$y = 5 x + \frac{1}{2}$

Step 2

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 5$

$b = \frac{1}{2}$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $5$

y-intercept: $(0, \frac{1}{2})$

Slope: $5$

y-intercept: $(0, \frac{1}{2})$

Step 3

Find the Slope and y-intercept 2(y+1)=10x+3

Related Questions

Support LCMGCF.com by disabling your adblocker.