Find the Slope and y-intercept (2001,6680) , (1998,4760)

$(2001, 6680)$ , $(1998, 4760)$

Step 1

Find the value of the slope.

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{4760 - (6680)}{1998 - (2001)}$

Simplify.

Simplify the numerator.

Multiply $- 1$ by $6680$ .

$m = \frac{4760 - 6680}{1998 - (2001)}$

Subtract $6680$ from $4760$ .

$m = \frac{- 1920}{1998 - (2001)}$

Simplify the denominator.

Multiply $- 1$ by $2001$ .

$m = \frac{- 1920}{1998 - 2001}$

Subtract $2001$ from $1998$ .

$m = \frac{- 1920}{- 3}$

Divide $- 1920$ by $- 3$ .

$m = 640$

Step 2

Find the value of the y-intercept.

Substitute the value of $m$ into the slope-intercept form of the equation, $y = m x + b$ .

$y = (640) \cdot x + b$

Substitute the value of $x$ into the slope-intercept form of the equation, $y = m x + b$ .

$y = (640) \cdot (2001) + b$

Substitute the value of $y$ into the slope-intercept form of the equation, $y = m x + b$ .

$6680 = (640) \cdot (2001) + b$

Rewrite the equation as $(640) \cdot (2001) + b = 6680$ .

$(640) \cdot (2001) + b = 6680$

Multiply $640$ by $2001$ .

$1280640 + b = 6680$

Move all terms not containing $b$ to the right side of the equation.

Subtract $1280640$ from both sides of the equation.

$b = 6680 - 1280640$

Subtract $1280640$ from $6680$ .

$b = - 1273960$

Step 3

List the slope and y-intercept.

Slope: $640$

y-intercept: $(0, - 1273960)$

Step 4

Find the Slope and y-intercept (2001,6680) , (1998,4760)

Related Questions

Support LCMGCF.com by disabling your adblocker.