Find the Slope and y-intercept (3,6) , (-2,1)

$(3, 6)$ , $(- 2, 1)$

Step 1

Find the value of the slope.

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{1 - (6)}{- 2 - (3)}$

Simplify.

Simplify the numerator.

Multiply $- 1$ by $6$ .

$m = \frac{1 - 6}{- 2 - (3)}$

Subtract $6$ from $1$ .

$m = \frac{- 5}{- 2 - (3)}$

Simplify the denominator.

Multiply $- 1$ by $3$ .

$m = \frac{- 5}{- 2 - 3}$

Subtract $3$ from $- 2$ .

$m = \frac{- 5}{- 5}$

Divide $- 5$ by $- 5$ .

$m = 1$

Step 2

Find the value of the y-intercept.

Substitute the value of $m$ into the slope-intercept form of the equation, $y = m x + b$ .

$y = (1) \cdot x + b$

Substitute the value of $x$ into the slope-intercept form of the equation, $y = m x + b$ .

$y = (1) \cdot (3) + b$

Substitute the value of $y$ into the slope-intercept form of the equation, $y = m x + b$ .

$6 = (1) \cdot (3) + b$

Rewrite the equation as $(1) \cdot (3) + b = 6$ .

$(1) \cdot (3) + b = 6$

Multiply $3$ by $1$ .

$3 + b = 6$

Move all terms not containing $b$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$b = 6 - 3$

Subtract $3$ from $6$ .

$b = 3$

Step 3

List the slope and y-intercept.

Slope: $1$

y-intercept: $(0, 3)$

Step 4

Find the Slope and y-intercept (3,6) , (-2,1)

Related Questions

Support LCMGCF.com by disabling your adblocker.