Find the Slope and y-intercept t(x)=(4x-2)/8

$t (x) = \frac{4 x - 2}{8}$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify the right side.

Cancel the common factor of $4 x - 2$ and $8$ .

Factor $2$ out of $4 x$ .

$y = \frac{2 (2 x) - 2}{8}$

Factor $2$ out of $- 2$ .

$y = \frac{2 (2 x) + 2 (- 1)}{8}$

Factor $2$ out of $2 (2 x) + 2 (- 1)$ .

$y = \frac{2 (2 x - 1)}{8}$

Cancel the common factors.

Factor $2$ out of $8$ .

$y = \frac{2 (2 x - 1)}{2 (4)}$

Cancel the common factor.

$y = \frac{2 (2 x - 1)}{2 \cdot 4}$

Rewrite the expression.

$y = \frac{2 x - 1}{4}$

Simplify $\frac{2 x - 1}{4}$ .

Split the fraction $\frac{2 x - 1}{4}$ into two fractions.

$y = \frac{2 x}{4} + \frac{- 1}{4}$

Simplify each term.

Cancel the common factor of $2$ and $4$ .

Factor $2$ out of $2 x$ .

$y = \frac{2 (x)}{4} + \frac{- 1}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$y = \frac{2 x}{2 \cdot 2} + \frac{- 1}{4}$

Cancel the common factor.

$y = \frac{2 x}{2 \cdot 2} + \frac{- 1}{4}$

Rewrite the expression.

$y = \frac{x}{2} + \frac{- 1}{4}$

Move the negative in front of the fraction.

$y = \frac{x}{2} - \frac{1}{4}$

Reorder terms.

$y = \frac{1}{2} x - \frac{1}{4}$

Step 2

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = \frac{1}{2}$

$b = - \frac{1}{4}$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $\frac{1}{2}$

y-intercept: $(0, - \frac{1}{4})$

Slope: $\frac{1}{2}$

y-intercept: $(0, - \frac{1}{4})$

Step 3

Find the Slope and y-intercept t(x)=(4x-2)/8

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