Find the Slope of a Parallel Line 2x+8y=-3

$2 x + 8 y = - 3$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $2 x$ from both sides of the equation.

$8 y = - 3 - 2 x$

Divide each term in $8 y = - 3 - 2 x$ by $8$ and simplify.

Divide each term in $8 y = - 3 - 2 x$ by $8$ .

$\frac{8 y}{8} = \frac{- 3}{8} + \frac{- 2 x}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 y}{8} = \frac{- 3}{8} + \frac{- 2 x}{8}$

Divide $y$ by $1$ .

$y = \frac{- 3}{8} + \frac{- 2 x}{8}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$y = - \frac{3}{8} + \frac{- 2 x}{8}$

Cancel the common factor of $- 2$ and $8$ .

Factor $2$ out of $- 2 x$ .

$y = - \frac{3}{8} + \frac{2 (- x)}{8}$

Cancel the common factors.

Factor $2$ out of $8$ .

$y = - \frac{3}{8} + \frac{2 (- x)}{2 (4)}$

Cancel the common factor.

$y = - \frac{3}{8} + \frac{2 (- x)}{2 \cdot 4}$

Rewrite the expression.

$y = - \frac{3}{8} + \frac{- x}{4}$

Move the negative in front of the fraction.

$y = - \frac{3}{8} - \frac{x}{4}$

Write in $y = m x + b$ form.

Reorder $- \frac{3}{8}$ and $- \frac{x}{4}$ .

$y = - \frac{x}{4} - \frac{3}{8}$

Reorder terms.

$y = - (\frac{1}{4} x) - \frac{3}{8}$

Remove parentheses.

$y = - \frac{1}{4} x - \frac{3}{8}$

Step 2

Using the slope-intercept form, the slope is $- \frac{1}{4}$ .

$m = - \frac{1}{4}$

Step 3

All lines that are parallel to $y = - \frac{1}{4} x - \frac{3}{8}$ have the same slope of $- \frac{1}{4}$ .

$m_{parallel} = - \frac{1}{4}$

Step 4

Find the Slope of a Parallel Line 2x+8y=-3

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