Find the Slope of a Parallel Line 7x-4y=-2

$7 x - 4 y = - 2$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $7 x$ from both sides of the equation.

$- 4 y = - 2 - 7 x$

Divide each term in $- 4 y = - 2 - 7 x$ by $- 4$ and simplify.

Divide each term in $- 4 y = - 2 - 7 x$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{- 2}{- 4} + \frac{- 7 x}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{- 2}{- 4} + \frac{- 7 x}{- 4}$

Divide $y$ by $1$ .

$y = \frac{- 2}{- 4} + \frac{- 7 x}{- 4}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 2$ and $- 4$ .

Factor $- 2$ out of $- 2$ .

$y = \frac{- 2 (1)}{- 4} + \frac{- 7 x}{- 4}$

Cancel the common factors.

Factor $- 2$ out of $- 4$ .

$y = \frac{- 2 \cdot 1}{- 2 \cdot 2} + \frac{- 7 x}{- 4}$

Cancel the common factor.

$y = \frac{- 2 \cdot 1}{- 2 \cdot 2} + \frac{- 7 x}{- 4}$

Rewrite the expression.

$y = \frac{1}{2} + \frac{- 7 x}{- 4}$

Dividing two negative values results in a positive value.

$y = \frac{1}{2} + \frac{7 x}{4}$

Write in $y = m x + b$ form.

Reorder $\frac{1}{2}$ and $\frac{7 x}{4}$ .

$y = \frac{7 x}{4} + \frac{1}{2}$

Reorder terms.

$y = \frac{7}{4} x + \frac{1}{2}$

Step 2

Using the slope-intercept form, the slope is $\frac{7}{4}$ .

$m = \frac{7}{4}$

Step 3

All lines that are parallel to $y = \frac{7}{4} x + \frac{1}{2}$ have the same slope of $\frac{7}{4}$ .

$m_{parallel} = \frac{7}{4}$

Step 4