Find the Slope of a Parallel Line 7x+4y=3

$7 x + 4 y = 3$

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $7 x$ from both sides of the equation.

$4 y = 3 - 7 x$

Divide each term in $4 y = 3 - 7 x$ by $4$ and simplify.

Divide each term in $4 y = 3 - 7 x$ by $4$ .

$\frac{4 y}{4} = \frac{3}{4} + \frac{- 7 x}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 y}{4} = \frac{3}{4} + \frac{- 7 x}{4}$

Divide $y$ by $1$ .

$y = \frac{3}{4} + \frac{- 7 x}{4}$

Simplify the right side.

Move the negative in front of the fraction.

$y = \frac{3}{4} - \frac{7 x}{4}$

Write in $y = m x + b$ form.

Reorder $\frac{3}{4}$ and $- \frac{7 x}{4}$ .

$y = - \frac{7 x}{4} + \frac{3}{4}$

Reorder terms.

$y = - (\frac{7}{4} x) + \frac{3}{4}$

Remove parentheses.

$y = - \frac{7}{4} x + \frac{3}{4}$

Using the slope-intercept form, the slope is $- \frac{7}{4}$ .

$m = - \frac{7}{4}$

All lines that are parallel to $y = - \frac{7}{4} x + \frac{3}{4}$ have the same slope of $- \frac{7}{4}$ .

$m_{parallel} = - \frac{7}{4}$