Find the Slope of a Parallel Line -8x-2y=-8

$- 8 x - 2 y = - 8$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Add $8 x$ to both sides of the equation.

$- 2 y = - 8 + 8 x$

Divide each term in $- 2 y = - 8 + 8 x$ by $- 2$ and simplify.

Divide each term in $- 2 y = - 8 + 8 x$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 8}{- 2} + \frac{8 x}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 8}{- 2} + \frac{8 x}{- 2}$

Divide $y$ by $1$ .

$y = \frac{- 8}{- 2} + \frac{8 x}{- 2}$

Simplify the right side.

Simplify each term.

Divide $- 8$ by $- 2$ .

$y = 4 + \frac{8 x}{- 2}$

Cancel the common factor of $8$ and $- 2$ .

Factor $2$ out of $8 x$ .

$y = 4 + \frac{2 (4 x)}{- 2}$

Move the negative one from the denominator of $\frac{4 x}{- 1}$ .

$y = 4 - 1 \cdot (4 x)$

Rewrite $- 1 \cdot (4 x)$ as $- (4 x)$ .

$y = 4 - (4 x)$

Multiply $4$ by $- 1$ .

$y = 4 - 4 x$

Reorder $4$ and $- 4 x$ .

$y = - 4 x + 4$

Step 2

Using the slope-intercept form, the slope is $- 4$ .

$m = - 4$

Step 3

All lines that are parallel to $y = - 4 x + 4$ have the same slope of $- 4$ .

$m_{parallel} = - 4$

Step 4