Find the Slope of a Parallel Line 8x-3y=-9

$8 x - 3 y = - 9$

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $8 x$ from both sides of the equation.

$- 3 y = - 9 - 8 x$

Divide each term in $- 3 y = - 9 - 8 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = - 9 - 8 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{- 9}{- 3} + \frac{- 8 x}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{- 9}{- 3} + \frac{- 8 x}{- 3}$

Divide $y$ by $1$ .

$y = \frac{- 9}{- 3} + \frac{- 8 x}{- 3}$

Simplify the right side.

Simplify each term.

Divide $- 9$ by $- 3$ .

$y = 3 + \frac{- 8 x}{- 3}$

Dividing two negative values results in a positive value.

$y = 3 + \frac{8 x}{3}$

Write in $y = m x + b$ form.

Reorder $3$ and $\frac{8 x}{3}$ .

$y = \frac{8 x}{3} + 3$

Reorder terms.

$y = \frac{8}{3} x + 3$

Using the slope-intercept form, the slope is $\frac{8}{3}$ .

$m = \frac{8}{3}$

All lines that are parallel to $y = \frac{8}{3} x + 3$ have the same slope of $\frac{8}{3}$ .

$m_{parallel} = \frac{8}{3}$