Find the Slope of a Parallel Line x-y=8

$x - y = 8$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $x$ from both sides of the equation.

$- y = 8 - x$

Divide each term in $- y = 8 - x$ by $- 1$ and simplify.

Divide each term in $- y = 8 - x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{8}{- 1} + \frac{- x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{8}{- 1} + \frac{- x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{8}{- 1} + \frac{- x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $8$ by $- 1$ .

$y = - 8 + \frac{- x}{- 1}$

Dividing two negative values results in a positive value.

$y = - 8 + \frac{x}{1}$

Divide $x$ by $1$ .

$y = - 8 + x$

Reorder $- 8$ and $x$ .

$y = x - 8$

Step 2

Using the slope-intercept form, the slope is $1$ .

$m = 1$

Step 3

All lines that are parallel to $y = x - 8$ have the same slope of $1$ .

$m_{parallel} = 1$

Step 4