Find the Slope of a Parallel Line y=-4/3x+1

$y = - \frac{4}{3} x + 1$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify the right side.

Simplify each term.

Combine $x$ and $\frac{4}{3}$ .

$y = - \frac{x \cdot 4}{3} + 1$

Move $4$ to the left of $x$ .

$y = - \frac{4 x}{3} + 1$

Write in $y = m x + b$ form.

Reorder terms.

$y = - (\frac{4}{3} x) + 1$

Remove parentheses.

$y = - \frac{4}{3} x + 1$

Step 2

Using the slope-intercept form, the slope is $- \frac{4}{3}$ .

$m = - \frac{4}{3}$

Step 3

All lines that are parallel to $y = - \frac{4}{3} x + 1$ have the same slope of $- \frac{4}{3}$ .

$m_{parallel} = - \frac{4}{3}$

Step 4