Find the Slope of a Perpendicular Line 4x-12y=2

$4 x - 12 y = 2$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $4 x$ from both sides of the equation.

$- 12 y = 2 - 4 x$

Divide each term in $- 12 y = 2 - 4 x$ by $- 12$ and simplify.

Divide each term in $- 12 y = 2 - 4 x$ by $- 12$ .

$\frac{- 12 y}{- 12} = \frac{2}{- 12} + \frac{- 4 x}{- 12}$

Simplify the left side.

Cancel the common factor of $- 12$ .

Cancel the common factor.

$\frac{- 12 y}{- 12} = \frac{2}{- 12} + \frac{- 4 x}{- 12}$

Divide $y$ by $1$ .

$y = \frac{2}{- 12} + \frac{- 4 x}{- 12}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $2$ and $- 12$ .

Factor $2$ out of $2$ .

$y = \frac{2 (1)}{- 12} + \frac{- 4 x}{- 12}$

Cancel the common factors.

Factor $2$ out of $- 12$ .

$y = \frac{2 \cdot 1}{2 \cdot - 6} + \frac{- 4 x}{- 12}$

Cancel the common factor.

$y = \frac{2 \cdot 1}{2 \cdot - 6} + \frac{- 4 x}{- 12}$

Rewrite the expression.

$y = \frac{1}{- 6} + \frac{- 4 x}{- 12}$

Move the negative in front of the fraction.

$y = - \frac{1}{6} + \frac{- 4 x}{- 12}$

Cancel the common factor of $- 4$ and $- 12$ .

Factor $- 4$ out of $- 4 x$ .

$y = - \frac{1}{6} + \frac{- 4 (x)}{- 12}$

Cancel the common factors.

Factor $- 4$ out of $- 12$ .

$y = - \frac{1}{6} + \frac{- 4 (x)}{- 4 (3)}$

Cancel the common factor.

$y = - \frac{1}{6} + \frac{- 4 x}{- 4 \cdot 3}$

Rewrite the expression.

$y = - \frac{1}{6} + \frac{x}{3}$

Write in $y = m x + b$ form.

Reorder $- \frac{1}{6}$ and $\frac{x}{3}$ .

$y = \frac{x}{3} - \frac{1}{6}$

Reorder terms.

$y = \frac{1}{3} x - \frac{1}{6}$

Step 2

Using the slope-intercept form, the slope is $\frac{1}{3}$ .

$m = \frac{1}{3}$

Step 3

The equation of a perpendicular line to $y = \frac{1}{3} x - \frac{1}{6}$ must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{\frac{1}{3}}$

Step 4

Simplify the result.

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = - (1 \cdot 3)$

Multiply $- (1 \cdot 3)$ .

Multiply $3$ by $1$ .

$m_{perpendicular} = - 1 \cdot 3$

Multiply $- 1$ by $3$ .

$m_{perpendicular} = - 3$

Step 5

Find the Slope of a Perpendicular Line 4x-12y=2

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