Find the Slope of a Perpendicular Line 4x-6y=8

$4 x - 6 y = 8$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $4 x$ from both sides of the equation.

$- 6 y = 8 - 4 x$

Divide each term in $- 6 y = 8 - 4 x$ by $- 6$ and simplify.

Divide each term in $- 6 y = 8 - 4 x$ by $- 6$ .

$\frac{- 6 y}{- 6} = \frac{8}{- 6} + \frac{- 4 x}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 y}{- 6} = \frac{8}{- 6} + \frac{- 4 x}{- 6}$

Divide $y$ by $1$ .

$y = \frac{8}{- 6} + \frac{- 4 x}{- 6}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $8$ and $- 6$ .

Factor $2$ out of $8$ .

$y = \frac{2 (4)}{- 6} + \frac{- 4 x}{- 6}$

Cancel the common factors.

Factor $2$ out of $- 6$ .

$y = \frac{2 \cdot 4}{2 \cdot - 3} + \frac{- 4 x}{- 6}$

Cancel the common factor.

$y = \frac{2 \cdot 4}{2 \cdot - 3} + \frac{- 4 x}{- 6}$

Rewrite the expression.

$y = \frac{4}{- 3} + \frac{- 4 x}{- 6}$

Move the negative in front of the fraction.

$y = - \frac{4}{3} + \frac{- 4 x}{- 6}$

Cancel the common factor of $- 4$ and $- 6$ .

Factor $- 2$ out of $- 4 x$ .

$y = - \frac{4}{3} + \frac{- 2 (2 x)}{- 6}$

Cancel the common factors.

Factor $- 2$ out of $- 6$ .

$y = - \frac{4}{3} + \frac{- 2 (2 x)}{- 2 (3)}$

Cancel the common factor.

$y = - \frac{4}{3} + \frac{- 2 (2 x)}{- 2 \cdot 3}$

Rewrite the expression.

$y = - \frac{4}{3} + \frac{2 x}{3}$

Write in $y = m x + b$ form.

Reorder $- \frac{4}{3}$ and $\frac{2 x}{3}$ .

$y = \frac{2 x}{3} - \frac{4}{3}$

Reorder terms.

$y = \frac{2}{3} x - \frac{4}{3}$

Step 2

Using the slope-intercept form, the slope is $\frac{2}{3}$ .

$m = \frac{2}{3}$

Step 3

The equation of a perpendicular line to $y = \frac{2}{3} x - \frac{4}{3}$ must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{\frac{2}{3}}$

Step 4

Simplify the result.

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = - (1 (\frac{3}{2}))$

Multiply $\frac{3}{2}$ by $1$ .

$m_{perpendicular} = - \frac{3}{2}$

Step 5

Find the Slope of a Perpendicular Line 4x-6y=8

Related Questions

Support LCMGCF.com by disabling your adblocker.