Find the Slope of a Perpendicular Line 8x+6y=4

$8 x + 6 y = 4$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $8 x$ from both sides of the equation.

$6 y = 4 - 8 x$

Divide each term in $6 y = 4 - 8 x$ by $6$ and simplify.

Divide each term in $6 y = 4 - 8 x$ by $6$ .

$\frac{6 y}{6} = \frac{4}{6} + \frac{- 8 x}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 y}{6} = \frac{4}{6} + \frac{- 8 x}{6}$

Divide $y$ by $1$ .

$y = \frac{4}{6} + \frac{- 8 x}{6}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $4$ and $6$ .

Factor $2$ out of $4$ .

$y = \frac{2 (2)}{6} + \frac{- 8 x}{6}$

Cancel the common factors.

Factor $2$ out of $6$ .

$y = \frac{2 \cdot 2}{2 \cdot 3} + \frac{- 8 x}{6}$

Cancel the common factor.

$y = \frac{2 \cdot 2}{2 \cdot 3} + \frac{- 8 x}{6}$

Rewrite the expression.

$y = \frac{2}{3} + \frac{- 8 x}{6}$

Cancel the common factor of $- 8$ and $6$ .

Factor $2$ out of $- 8 x$ .

$y = \frac{2}{3} + \frac{2 (- 4 x)}{6}$

Cancel the common factors.

Factor $2$ out of $6$ .

$y = \frac{2}{3} + \frac{2 (- 4 x)}{2 (3)}$

Cancel the common factor.

$y = \frac{2}{3} + \frac{2 (- 4 x)}{2 \cdot 3}$

Rewrite the expression.

$y = \frac{2}{3} + \frac{- 4 x}{3}$

Move the negative in front of the fraction.

$y = \frac{2}{3} - \frac{4 x}{3}$

Write in $y = m x + b$ form.

Reorder $\frac{2}{3}$ and $- \frac{4 x}{3}$ .

$y = - \frac{4 x}{3} + \frac{2}{3}$

Reorder terms.

$y = - (\frac{4}{3} x) + \frac{2}{3}$

Remove parentheses.

$y = - \frac{4}{3} x + \frac{2}{3}$

Step 2

Using the slope-intercept form, the slope is $- \frac{4}{3}$ .

$m = - \frac{4}{3}$

Step 3

The equation of a perpendicular line to $y = - \frac{4}{3} x + \frac{2}{3}$ must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{- \frac{4}{3}}$

Step 4

Simplify the result.

Cancel the common factor of $1$ and $- 1$ .

Rewrite $1$ as $- 1 (- 1)$ .

$m_{perpendicular} = - \frac{- 1 \cdot - 1}{- \frac{4}{3}}$

Move the negative in front of the fraction.

$m_{perpendicular} = \frac{1}{\frac{4}{3}}$

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = 1 (\frac{3}{4})$

Multiply $\frac{3}{4}$ by $1$ .

$m_{perpendicular} = \frac{3}{4}$

Multiply $- - \frac{3}{4}$ .

Multiply $- 1$ by $- 1$ .

$m_{perpendicular} = 1 (\frac{3}{4})$

Multiply $\frac{3}{4}$ by $1$ .

$m_{perpendicular} = \frac{3}{4}$

Step 5

Find the Slope of a Perpendicular Line 8x+6y=4

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