Find the Slope of a Perpendicular Line x+2y=8

$x + 2 y = 8$

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $x$ from both sides of the equation.

$2 y = 8 - x$

Divide each term in $2 y = 8 - x$ by $2$ and simplify.

Divide each term in $2 y = 8 - x$ by $2$ .

$\frac{2 y}{2} = \frac{8}{2} + \frac{- x}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{8}{2} + \frac{- x}{2}$

Divide $y$ by $1$ .

$y = \frac{8}{2} + \frac{- x}{2}$

Simplify the right side.

Simplify each term.

Divide $8$ by $2$ .

$y = 4 + \frac{- x}{2}$

Move the negative in front of the fraction.

$y = 4 - \frac{x}{2}$

Write in $y = m x + b$ form.

Reorder $4$ and $- \frac{x}{2}$ .

$y = - \frac{x}{2} + 4$

Reorder terms.

$y = - (\frac{1}{2} x) + 4$

Remove parentheses.

$y = - \frac{1}{2} x + 4$

Using the slope-intercept form, the slope is $- \frac{1}{2}$ .

$m = - \frac{1}{2}$

The equation of a perpendicular line to $y = - \frac{1}{2} x + 4$ must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{- \frac{1}{2}}$

Simplify the result.

Cancel the common factor of $1$ and $- 1$ .

Rewrite $1$ as $- 1 (- 1)$ .

$m_{perpendicular} = - \frac{- 1 \cdot - 1}{- \frac{1}{2}}$

Move the negative in front of the fraction.

$m_{perpendicular} = \frac{1}{\frac{1}{2}}$

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = 1 \cdot 2$

Multiply $2$ by $1$ .

$m_{perpendicular} = - (- 1 \cdot 2)$

Multiply $- 1$ by $2$ .

$m_{perpendicular} = 2$

Multiply $- 1$ by $- 2$ .

$m_{perpendicular} = 2$

Find the Slope of a Perpendicular Line x+2y=8

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