Find the Slope of a Perpendicular Line y+2/3x=2

$y + \frac{2}{3} x = 2$

Step 1

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify the left side.

Combine $\frac{2}{3}$ and $x$ .

$y + \frac{2 x}{3} = 2$

Subtract $\frac{2 x}{3}$ from both sides of the equation.

$y = 2 - \frac{2 x}{3}$

Write in $y = m x + b$ form.

Reorder $2$ and $- \frac{2 x}{3}$ .

$y = - \frac{2 x}{3} + 2$

Reorder terms.

$y = - (\frac{2}{3} x) + 2$

Remove parentheses.

$y = - \frac{2}{3} x + 2$

Step 2

Using the slope-intercept form, the slope is $- \frac{2}{3}$ .

$m = - \frac{2}{3}$

Step 3

The equation of a perpendicular line to $y = - \frac{2}{3} x + 2$ must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{- \frac{2}{3}}$

Step 4

Simplify the result.

Cancel the common factor of $1$ and $- 1$ .

Rewrite $1$ as $- 1 (- 1)$ .

$m_{perpendicular} = - \frac{- 1 \cdot - 1}{- \frac{2}{3}}$

Move the negative in front of the fraction.

$m_{perpendicular} = \frac{1}{\frac{2}{3}}$

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = 1 (\frac{3}{2})$

Multiply $\frac{3}{2}$ by $1$ .

$m_{perpendicular} = \frac{3}{2}$

Multiply $- - \frac{3}{2}$ .

Multiply $- 1$ by $- 1$ .

$m_{perpendicular} = 1 (\frac{3}{2})$

Multiply $\frac{3}{2}$ by $1$ .

$m_{perpendicular} = \frac{3}{2}$

Step 5