Find the Slope of a Perpendicular Line y=-5x+8

$y = - 5 x + 8$

Step 1

Use the slope-intercept form to find the slope.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Using the slope-intercept form, the slope is $- 5$ .

$m = - 5$

Step 2

The equation of a perpendicular line to $y = - 5 x + 8$ must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{- 5}$

Step 3

Simplify the result.

Move the negative in front of the fraction.

$m_{perpendicular} = \frac{1}{5}$

Multiply $- - \frac{1}{5}$ .

Multiply $- 1$ by $- 1$ .

$m_{perpendicular} = 1 (\frac{1}{5})$

Multiply $\frac{1}{5}$ by $1$ .

$m_{perpendicular} = \frac{1}{5}$

Step 4