Find the Slope of a Perpendicular Line y=8x-3

$y = 8 x - 3$

Step 1

Use the slope-intercept form to find the slope.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Using the slope-intercept form, the slope is $8$ .

$m = 8$

Step 2

The equation of a perpendicular line to $y = 8 x - 3$ must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{8}$

Step 3