Find the Standard Form of the Parabola f(x)=-(x+2)^2

$f (x) = - {(x + 2)}^{2}$

Step 1

Write $f (x) = - {(x + 2)}^{2}$ as an equation.

$y = - {(x + 2)}^{2}$

Step 2

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$- {(x + 2)}^{2} = y$

Step 3

Divide each term in $- {(x + 2)}^{2} = y$ by $- 1$ and simplify.

Divide each term in $- {(x + 2)}^{2} = y$ by $- 1$ .

$\frac{- {(x + 2)}^{2}}{- 1} = \frac{y}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{{(x + 2)}^{2}}{1} = \frac{y}{- 1}$

Divide ${(x + 2)}^{2}$ by $1$ .

${(x + 2)}^{2} = \frac{y}{- 1}$

Simplify the right side.

Move the negative one from the denominator of $\frac{y}{- 1}$ .

${(x + 2)}^{2} = - 1 \cdot y$

Rewrite $- 1 \cdot y$ as $- y$ .

${(x + 2)}^{2} = - y$