Find the Standard Form of the Parabola x=17(y-8)^2+9

$x = 17 {(y - 8)}^{2} + 9$

Since $y$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$17 {(y - 8)}^{2} + 9 = x$

Subtract $9$ from both sides of the equation.

$17 {(y - 8)}^{2} = x - 9$

Divide each term in $17 {(y - 8)}^{2} = x - 9$ by $17$ and simplify.

Divide each term in $17 {(y - 8)}^{2} = x - 9$ by $17$ .

$\frac{17 {(y - 8)}^{2}}{17} = \frac{x}{17} + \frac{- 9}{17}$

Simplify the left side.

Cancel the common factor of $17$ .

Cancel the common factor.

$\frac{17 {(y - 8)}^{2}}{17} = \frac{x}{17} + \frac{- 9}{17}$

Divide ${(y - 8)}^{2}$ by $1$ .

${(y - 8)}^{2} = \frac{x}{17} + \frac{- 9}{17}$

Simplify the right side.

Move the negative in front of the fraction.

${(y - 8)}^{2} = \frac{x}{17} - \frac{9}{17}$

Factor.

Combine the numerators over the common denominator.

${(y - 8)}^{2} = \frac{x - 9}{17}$

Reorder terms.

${(y - 8)}^{2} = \frac{1}{17} (x - 9)$