Find the Standard Form of the Parabola y^2+2y-2x-3=0

$y^{2} + 2 y - 2 x - 3 = 0$

Step 1

Move all terms not containing $y$ to the right side of the equation.

Add $2 x$ to both sides of the equation.

$y^{2} + 2 y - 3 = 2 x$

Add $3$ to both sides of the equation.

$y^{2} + 2 y = 2 x + 3$

Step 2

Complete the square.

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 2$

$c = 0 = 2 x + 3$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e = 2 x + 3$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{2}{2 \cdot 1}$

Cancel the common factor of $2$ .

Cancel the common factor.

$d = \frac{2}{2 \cdot 1}$

Rewrite the expression.

$d = 1$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{2^{2}}{4 \cdot 1}$

Simplify the right side.

Simplify each term.

Raise $2$ to the power of $2$ .

$e = 0 - \frac{4}{4 \cdot 1}$

Multiply $4$ by $1$ .

$e = 0 - \frac{4}{4}$

Cancel the common factor of $4$ .

Cancel the common factor.

$e = 0 - \frac{4}{4}$

Rewrite the expression.

$e = 0 - 1 \cdot 1$

Multiply $- 1$ by $1$ .

$e = 0 - 1$

Subtract $1$ from $0$ .

$e = - 1$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(y + 1)}^{2} - 1$ .

${(y + 1)}^{2} - 1 = 2 x + 3$

Step 3

Move all terms not containing $y$ to the right side of the equation.

Add $1$ to both sides of the equation.

${(y + 1)}^{2} = 2 x + 3 + 1$

Add $3$ and $1$ .

${(y + 1)}^{2} = 2 x + 4$

Step 4

Factor $2$ out of $2 x + 4$ .

Factor $2$ out of $2 x$ .

${(y + 1)}^{2} = 2 (x) + 4$

Factor $2$ out of $4$ .

${(y + 1)}^{2} = 2 x + 2 \cdot 2$

Factor $2$ out of $2 x + 2 \cdot 2$ .

${(y + 1)}^{2} = 2 (x + 2)$

Find the Standard Form of the Parabola y^2+2y-2x-3=0

Related Questions

Support LCMGCF.com by disabling your adblocker.