Find the Standard Form of the Parabola y^2+8x+8=0

$y^{2} + 8 x + 8 = 0$

Move all terms not containing $y$ to the right side of the equation.

Subtract $8 x$ from both sides of the equation.

$y^{2} + 8 = - 8 x$

Subtract $8$ from both sides of the equation.

$y^{2} = - 8 x - 8$

Factor.

Factor $8$ out of $- 8 x - 8$ .

Factor $8$ out of $- 8 x$ .

$y^{2} = 8 (- x) - 8$

Factor $8$ out of $- 8$ .

$y^{2} = 8 (- x) + 8 (- 1)$

Factor $8$ out of $8 (- x) + 8 (- 1)$ .

$y^{2} = 8 (- x - 1)$

Factor $- 1$ out of $- x$ .

$y^{2} = 8 (- (x) - 1)$

Rewrite $- 1$ as $- 1 (1)$ .

$y^{2} = 8 (- (x) - 1 (1))$

Factor $- 1$ out of $- (x) - 1 (1)$ .

$y^{2} = 8 (- (x + 1))$

Multiply $- 1$ by $8$ .

$y^{2} = - 8 (x + 1)$