Find the Sum and Product of the Roots of the Quadratic Equation 6x^2+12x-18=0

$6 x^{2} + 12 x - 18 = 0$

Step 1

Find $a$ , $b$ , and $c$ .

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 6$ , $b = 12$ , $c = - 18$

Step 2

Substitute the values into the sum of roots formula $- \frac{b}{a}$ .

Divide $- 12$ by $6$ .

$- 2$

Step 3

Substitute the values into the product of roots formula $\frac{c}{a}$ .

Divide $- 18$ by $6$ .

$- 3$

Step 4

List the results.

Sum of the roots is $- 2$

Product of the roots is $- 3$