Find the Sum and Product of the Roots of the Quadratic Equation x^2+x-56=0

$x^{2} + x - 56 = 0$

Find $a$ , $b$ , and $c$ .

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 1$ , $b = 1$ , $c = - 56$

Substitute the values into the sum of roots formula $- \frac{b}{a}$ .

Divide $- 1$ by $1$ .

$- 1$

Substitute the values into the product of roots formula $\frac{c}{a}$ .

Divide $- 56$ by $1$ .

$- 56$

List the results.

Sum of the roots is $- 1$

Product of the roots is $- 56$