Find the Sum of the Infinite Geometric Series 3/4 , -1/4 , 1/12

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by ${\displaystyle -\frac{1}{3}}$ gives the next term. In other words, ${\displaystyle a_n=a_1{r}^{n-1}}$.

Geometric Sequence: ${\displaystyle r=-\frac{1}{3}}$

The sum of a series ${\displaystyle S_n}$ is calculated using the formula ${\displaystyle S_n=\frac{a(1-r^n)}{1-r}}$. For the sum of an infinite geometric series ${\displaystyle S_{\infty }}$, as ${\displaystyle n}$ approaches ${\displaystyle \infty }$, ${\displaystyle 1-r^n}$ approaches ${\displaystyle 1}$. Thus, ${\displaystyle \frac{a(1-r^n)}{1-r}}$ approaches ${\displaystyle \frac{a}{1-r}}$.

The values ${\displaystyle a=\frac{3}{4}}$ and ${\displaystyle r=-\frac{1}{3}}$ can be put in the equation ${\displaystyle S_{\infty }}$.