Find the Symmetry y=7x^3

$y = 7 x^{3}$

There are three types of symmetry:

1. X-Axis Symmetry

2. Y-Axis Symmetry

3. Origin Symmetry

If $(x, y)$ exists on the graph, then the graph is symmetric about the:

1. X-Axis if $(x, - y)$ exists on the graph

2. Y-Axis if $(- x, y)$ exists on the graph

3. Origin if $(- x, - y)$ exists on the graph

Check if the graph is symmetric about the x-axis by plugging in $- y$ for $y$ .

$- y = 7 x^{3}$

Simplify the left side.

Remove parentheses.

$- y = 7 x^{3}$

Since the equation is not identical to the original equation, it is not symmetric to the x-axis.

Not symmetric to the x-axis

Check if the graph is symmetric about the y-axis by plugging in $- x$ for $x$ .

$y = 7 {(- x)}^{3}$

Simplify the right side.

Simplify $7 {(- x)}^{3}$ .

Apply the product rule to $- x$ .

$y = 7 ({(- 1)}^{3} x^{3})$

Raise $- 1$ to the power of $3$ .

$y = 7 (- x^{3})$

Multiply $- 1$ by $7$ .

$y = - 7 x^{3}$

Since the equation is not identical to the original equation, it is not symmetric to the y-axis.

Not symmetric to the y-axis

Check if the graph is symmetric about the origin by plugging in $- x$ for $x$ and $- y$ for $y$ .

$- y = 7 {(- x)}^{3}$

Solve for $y$ .

Simplify the left side.

Remove parentheses.

$- y = 7 {(- x)}^{3}$

Simplify the right side.

Simplify $7 {(- x)}^{3}$ .

Apply the product rule to $- x$ .

$- y = 7 ({(- 1)}^{3} x^{3})$

Raise $- 1$ to the power of $3$ .

$- y = 7 (- x^{3})$

Multiply $- 1$ by $7$ .

$- y = - 7 x^{3}$

Simplify the left side.

Multiply $- (- y)$ .

Multiply $- 1$ by $- 1$ .

$1 y = - (7 {(- x)}^{3})$

Multiply $y$ by $1$ .

$y = - (7 {(- x)}^{3})$

Simplify the right side.

Simplify $- (7 {(- x)}^{3})$ .

Apply the product rule to $- x$ .

$y = - (7 ({(- 1)}^{3} x^{3}))$

Multiply $- 1$ by ${(- 1)}^{3}$ by adding the exponents.

Move ${(- 1)}^{3}$ .

$y = {(- 1)}^{3} \cdot - 1 (7 (x^{3}))$

Multiply ${(- 1)}^{3}$ by $- 1$ .

Raise $- 1$ to the power of $1$ .

$y = {(- 1)}^{3} \cdot {(- 1)}^{1} (7 (x^{3}))$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y = {(- 1)}^{3 + 1} (7 (x^{3}))$

Add $3$ and $1$ .

$y = {(- 1)}^{4} (7 (x^{3}))$

Raise $- 1$ to the power of $4$ .

$y = 1 (7 (x^{3}))$

Multiply $7 (x^{3})$ by $1$ .

$y = 7 x^{3}$

Since the equation is identical to the original equation, it is symmetric to the origin.

Symmetric with respect to the origin

Find the Symmetry y=7x^3

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