Find the Tangent Given the Point (-11,-28)

To find the ${\displaystyle \tan \left(\theta \right)}$ between the x-axis and the line between the points ${\displaystyle (0,0)}$ and ${\displaystyle (-11,-28)}$, draw the triangle between the three points ${\displaystyle (0,0)}$, ${\displaystyle (-11,0)}$, and ${\displaystyle (-11,-28)}$.

${\displaystyle \tan \left(\theta \right)=\frac{\text{Opposite}}{\text{Adjacent}}}$ therefore ${\displaystyle \tan \left(\theta \right)=\frac{-28}{-11}}$.

Dividing two negative values results in a positive value.