Find the Tangent Given the Point (9,-2)

To find the ${\displaystyle \tan \left(\theta \right)}$ between the x-axis and the line between the points ${\displaystyle (0,0)}$ and ${\displaystyle (9,-2)}$, draw the triangle between the three points ${\displaystyle (0,0)}$, ${\displaystyle (9,0)}$, and ${\displaystyle (9,-2)}$.

Opposite : ${\displaystyle -2}$

Adjacent : ${\displaystyle 9}$

${\displaystyle \tan \left(\theta \right)=\frac{\text{Opposite}}{\text{Adjacent}}}$ therefore ${\displaystyle \tan \left(\theta \right)=\frac{-2}{9}}$.

Move the negative in front of the fraction.